The PV diagram shows four different possible | vedclass

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(C) For an ideal gas,the temperature $T$ is proportional to the product $PV$ (from $PV = nRT$).$1$. In process $A$ (isobaric expansion),$P$ is constan

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Only Processes $C$ and $D$

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(C) For an ideal gas,the temperature $T$ is proportional to the product $PV$ (from $PV = nRT$).$1$. In process $A$ (isobaric expansion),$P$ is constant and $V$ increases,so $PV$ increases,meaning the temperature $T$ increases.$2$. In process $B$ (isothermal expansion),$PV$ is constant,so the temperature $T$ remains constant.$3$. In process $C$ (adiabatic expansion),$P$ decreases and $V$ increases. Since the adiabatic curve is steeper than the isothermal curve,the product $PV$ decreases,so the temperature $T$ decreases.$4$. In process $D$ (isochoric compression),$V$ is constant and $P$ decreases,so $PV$ decreases,meaning the temperature $T$ decreases.Therefore,the temperature decreases in both processes $C$ and $D$. Hence,option $C$ is the correct answer.

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