The EAN of metal atoms in Fe(NO)_2(CO)_2 and | vedclass

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(C) The $EAN$ (Effective Atomic Number) is calculated using the formula: $EAN = Z - X + Y$,where $Z$ is the atomic number,$X$ is the oxidation state,a

Vedclass · Accepted Answer

$36, 36$

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(C) The $EAN$ (Effective Atomic Number) is calculated using the formula: $EAN = Z - X + Y$,where $Z$ is the atomic number,$X$ is the oxidation state,and $Y$ is the number of electrons donated by ligands.For $Fe(NO)_2(CO)_2$: The oxidation state of $Fe$ is $0$ (assuming $NO$ as $NO^+$ and $CO$ as neutral,or $NO$ as neutral and $CO$ as neutral depending on convention; in standard $EAN$ calculations for these complexes,$Fe$ is $0$). $Fe$ $(Z=26)$,$2 	imes CO$ ($2 	imes 2 = 4$ electrons),$2 	imes NO$ ($2 	imes 3 = 6$ electrons). $EAN = 26 - 0 + 10 = 36$.For $Co_2(CO)_8$: Each $Co$ $(Z=27)$ has one $Co-Co$ bond ($1$ electron) and $4$ $CO$ ligands ($8$ electrons). Oxidation state is $0$. $EAN = 27 - 0 + 9 = 36$.

The $EAN$ of metal atoms in $Fe(NO)_2(CO)_2$ and $Co_2(CO)_8$ respectively are

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