The T.V. transmission tower in Delhi has a he | vedclass

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(C) The formula for the maximum line-of-sight distance $d$ for a transmission tower of height $h$ is given by $d = \sqrt{2hR}$,where $R$ is the radius

Vedclass · Accepted Answer

$56$

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(C) The formula for the maximum line-of-sight distance $d$ for a transmission tower of height $h$ is given by $d = \sqrt{2hR}$,where $R$ is the radius of the earth.Given:Height of the tower,$h = 245 \ m = 0.245 \ km$.Radius of the earth,$R = 6.4 	imes 10^6 \ m = 6400 \ km$.Substituting these values into the formula:$d = \sqrt{2 	imes 0.245 	imes 6400}$$d = \sqrt{0.49 	imes 6400}$$d = \sqrt{0.49} 	imes \sqrt{6400}$$d = 0.7 	imes 80$$d = 56 \ km$.Thus,the broadcast can be received up to a distance of $56 \ km$.

The $T.V.$ transmission tower in Delhi has a height of $245 \ m$. The distance up to which the broadcast can be received (taking the radius of the earth to be $6.4 \times 10^6 \ m$) is .......... $km$.

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