The absolute configurations of the two chiral | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the absolute configuration $(R/S)$ at each chiral center,we assign priorities to the groups attached to each carbon using the Cahn-In

Vedclass · Accepted Answer

$2(R), 3(S)$

Vedclass · Answer

(A) To determine the absolute configuration $(R/S)$ at each chiral center,we assign priorities to the groups attached to each carbon using the Cahn-Ingold-Prelog $(CIP)$ rules.For carbon-$2$:Priorities: $1: -Br$,$2: -COOH$,$3: -CH(OH)CN$,$4: -H$.The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is counter-clockwise. Since the lowest priority group $(-H)$ is on a horizontal bond,the configuration is reversed from $S$ to $R$. Thus,carbon-$2$ is $2(R)$.For carbon-$3$:Priorities: $1: -OH$,$2: -CH(Br)COOH$,$3: -CN$,$4: -H$.The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise. Since the lowest priority group $(-H)$ is on a horizontal bond,the configuration is reversed from $R$ to $S$. Thus,carbon-$3$ is $3(S)$.Therefore,the configuration is $2(R), 3(S)$.

The absolute configurations of the two chiral centers in the following molecule are:

Similar Questions

If $f: R \rightarrow R$ is defined by $f(x)=[2x]-2[x]$ for $x \in R$,where $[x]$ is the greatest integer function,then the range of $f$ is:

$A$ salt $MX$ has $K_{sp} = 4 \times 10^{-10}$. What value of $K_{sp}$ must another salt $MX_3$ have if the molar solubility of the two salts is to be identical?

$A$ space $2.5 \ cm$ wide between two large plane surfaces is filled with oil. The force required to drag a very thin plate of area $0.5 \ m^2$ just midway between the surfaces at a speed of $0.5 \ m/s$ is $1 \ N$. The coefficient of viscosity in $kg/(m \cdot s)$ is:

The angle of elevation of a stationary cloud from a point $2500 \ m$ above a lake is $15^{\circ}$ and from the same point the angle of depression of its reflection in the lake is $45^{\circ}$. The height (in metres) of the cloud above the lake,given that $\cot 15^{\circ}=2+\sqrt{3}$,is

Identify the non-reducing sugar from the following.

Vedclass Test Series

Exam Paper Generator

Online Exam Module