The acceleration due to gravity near the surface of a planet of radius $R$ and density $d$ is proportional to

The radius of the Earth is $6400 \,km$ and the acceleration due to gravity is $g=10 \,ms^{-2}$. For the weight of a body of mass $5 \,kg$ to be zero at the equator,the rotational angular velocity of the Earth must be (in $rad/s$):

Suppose that the angular velocity of rotation of the earth is increased. Then,as a consequence:

Acceleration due to gravity at the surface of a planet is equal to that at the surface of the Earth,and its density is $1.5$ times that of the Earth. If the radius of the Earth is $R$,the radius of the planet is:

Which of the following statements are true about acceleration due to gravity?
$(a)$ '$g$' decreases in moving away from the centre if $r > R$
$(b)$ '$g$' decreases in moving towards the centre if $r < R$
$(c)$ '$g$' is zero at the centre of the Earth
$(d)$ '$g$' decreases if the Earth stops rotating on its axis

$A$ body weighs $144 \, N$ at the surface of the earth. When it is taken to a height of $h = 3R$,where $R$ is the radius of the earth,it would weigh .......... $N$.