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(D) The addition of $HBr$ to alkenes is an electrophilic addition reaction,which proceeds via the formation of a carbocation intermediate.Greater stab

Vedclass · Accepted Answer

$(CH_3)_2C = CH_2$

Vedclass · Answer

(D) The addition of $HBr$ to alkenes is an electrophilic addition reaction,which proceeds via the formation of a carbocation intermediate.Greater stability of the carbocation leads to a faster reaction rate.In $(CH_3)_2C = CH_2$,the addition of $H^+$ leads to the formation of a tertiary carbocation,$(CH_3)_3C^+$,which is the most stable among the given options due to the inductive effect and hyperconjugation of six $\alpha$-hydrogens.Therefore,$(CH_3)_2C = CH_2$ reacts most easily with $HBr$.

The addition of $HBr$ is easiest with

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