The adjacent figure shows a part of a horizontally stretched net. Section $AB$ is stretched with a force of $10 \,N$. The tensions in the sections $BC$ and $BF$ are

$A$ flexible chain of weight $W$ hangs between two fixed points $A$ and $B$ which are at the same horizontal level. The inclination of the chain with the horizontal at both the points of support is $\theta$. What is the tension of the chain at the mid point?

Can a stationary object remain stationary if multiple external forces act upon it?

As shown in the figure,the tension in the horizontal cord is $30 \, N$. The weight $W$ and the tension in the string $OA$ in Newton are:

$A$ particle is situated at the origin of a coordinate system. The following forces begin to act on the particle simultaneously (assuming the particle is initially at rest):
$\vec{F}_1 = 5\hat{i} - 5\hat{j} + 5\hat{k}$
$\vec{F}_2 = 2\hat{i} + 8\hat{j} + 6\hat{k}$
$\vec{F}_3 = -6\hat{i} + 4\hat{j} - 7\hat{k}$
$\vec{F}_4 = -\hat{i} - 3\hat{j} - 2\hat{k}$
Then the particle will move:

$A$ mass $M$ is suspended by a rope from a rigid support at $A$ as shown in the figure. Another rope is tied at point $B$,and it is pulled horizontally with a force $F$. If the string $AB$ makes an angle $\theta$ with the vertical in equilibrium,then the tension in the string $AB$ is: