The alkane formed on heating sodium butanoate | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction of sodium butanoate with sodalime $(NaOH + CaO)$ is a decarboxylation reaction. In this process,the carboxyl group $(-COO^-Na^+)$ is

Vedclass · Accepted Answer

Propane

Vedclass · Answer

(C) The reaction of sodium butanoate with sodalime $(NaOH + CaO)$ is a decarboxylation reaction. In this process,the carboxyl group $(-COO^-Na^+)$ is removed as $Na_2CO_3$,and the resulting alkane contains one carbon atom less than the parent carboxylic acid salt. Sodium butanoate $(CH_3CH_2CH_2COONa)$ has $4$ carbon atoms. Upon decarboxylation,it yields propane $(CH_3CH_2CH_3)$,which has $3$ carbon atoms. Reaction: $CH_3CH_2CH_2COONa + NaOH \xrightarrow[\Delta]{CaO} CH_3CH_2CH_3 + Na_2CO_3$

The alkane formed on heating sodium butanoate with sodalime is

Similar Questions

$R^{\prime}-X \xrightarrow{Na / \text{ether}} 2,3-\text{dimethylbutane}$. Identify $R^{\prime}$.

Pure methane can be produced by:

The chlorination of ethane is an example of which of the following types of reactions?

$n$-pentane and isopentane can be distinguished by

What is $Z$ in the following reaction?
$CH_3-CH_2-CO_2^{\ominus} Na^{\oplus} \stackrel{NaOH / CaO}{\longrightarrow} Z$

Vedclass Test Series

Exam Paper Generator

Online Exam Module