The amine which reacts with p-toluene sulphon | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction with $p$-toluene sulphonyl chloride (Hinsberg reagent) is used to distinguish between $1^\circ$,$2^\circ$,and $3^\circ$ amines.$1^\ci

Vedclass · Accepted Answer

$C_2H_5NH_2$

Vedclass · Answer

(A) The reaction with $p$-toluene sulphonyl chloride (Hinsberg reagent) is used to distinguish between $1^\circ$,$2^\circ$,and $3^\circ$ amines.$1^\circ$ amines $(R-NH_2)$ react to form an $N$-alkyl $p$-toluene sulphonamide,which contains an acidic hydrogen atom attached to the nitrogen. This makes the product soluble in alkali (forming a clear solution).Upon acidification of this clear solution,the $N$-alkyl $p$-toluene sulphonamide precipitates out as an insoluble compound.$2^\circ$ amines form a product that is insoluble in alkali,and $3^\circ$ amines do not react with the reagent.Therefore,the primary amine $C_2H_5NH_2$ is the correct answer.

List-$I$ (Reagents used)	List-$II$ (Compound with functional group detected)
$A.$ Alkaline solution of copper sulphate and sodium citrate	$I.$ $C_6H_5CH(OH)CH_3$
$B.$ Neutral $FeCl_3$ solution	$II.$ $CH_3CH(NH_2)CH_3$
$C.$ Alkaline chloroform solution	$III.$ $C_6H_5CH_2CHO$
$D.$ Potassium iodide and sodium hypochlorite	$IV.$ $m-C_2H_5C_6H_4OH$

The amine which reacts with $p$-toluene sulphonyl chloride to give a clear solution which on acidification gives an insoluble compound is:

Similar Questions

Identify Hinsberg's reagent from the following.

Which of the following compounds does not give the isocyanide test?

Hinsberg’s reagent is

How many of the following amine compounds form a product with Hinsberg's reagent $(C_6H_5SO_2Cl)$ that is soluble in $NaOH$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module