The amount of K_2Cr_2O_7 (equivalent weight 4 | vedclass

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Question

(D) The formula to calculate the mass $(W)$ of a solute in grams is given by: $W = \frac{N 	imes 	ext{equivalent weight} 	imes V(mL)}{1000}$ Given:

Vedclass · Accepted Answer

$0.2452$

Vedclass · Answer

(D) The formula to calculate the mass $(W)$ of a solute in grams is given by: $W = \frac{N 	imes 	ext{equivalent weight} 	imes V(mL)}{1000}$ Given: Normality $(N)$ = $0.05 \ N$ Equivalent weight = $49.04$ Volume $(V)$ = $100 \ mL$ Substituting the values: $W = \frac{0.05 	imes 49.04 	imes 100}{1000} = \frac{245.2}{1000} = 0.2452 \ g$ Therefore,the correct option is $(D)$.

The amount of $K_2Cr_2O_7$ (equivalent weight $49.04$) required to prepare $100 \ mL$ of its $0.05 \ N$ solution is ........ $g$.

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