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(A) Before closing the switch $S$,the potential difference across both capacitors is $V$. The left capacitor is connected to a battery of potential $V

Vedclass · Accepted Answer

Zero

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(A) Before closing the switch $S$,the potential difference across both capacitors is $V$. The left capacitor is connected to a battery of potential $V$,and the right capacitor is connected to another battery of potential $V$. When the switch $S$ is closed,the potential difference across both capacitors remains $V$ because they are connected in parallel to their respective batteries. Since there is no change in the potential difference across the capacitors,there is no redistribution of charge. Therefore,the change in the energy of the system is zero,and the heat liberated in the circuit is $H = 0$.

Calculate the amount of heat liberated in the circuit after closing the switch $S$.

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