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(C) The expression for the heat supplied at constant volume is given by $Q = n C_v \Delta T$.Here,$n$ is the number of moles,$C_v$ is the molar heat c

Vedclass · Accepted Answer

$1.81$

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(C) The expression for the heat supplied at constant volume is given by $Q = n C_v \Delta T$.Here,$n$ is the number of moles,$C_v$ is the molar heat capacity at constant volume,and $\Delta T$ is the change in temperature.Number of moles $n = \frac{m}{M} = \frac{35}{32} \ mol$.Oxygen is a diatomic gas,so its degree of freedom $f = 5$.Thus,$C_v = \frac{f}{2} R = \frac{5}{2} R$.Substituting the values: $Q = \left( \frac{35}{32} ight) 	imes \left( \frac{5}{2} 	imes 8.3 ight) 	imes 80$.$Q = \frac{35}{32} 	imes 5 	imes 8.3 	imes 40$.$Q = 35 	imes 5 	imes 8.3 	imes 1.25 = 1815.625 \ J$.$Q \approx 1.81 \ kJ$.

The amount of heat that must be supplied to $35 \ g$ of oxygen at room temperature to raise its temperature by $80^{\circ} C$ at constant volume is (molecular mass of oxygen is $32$ and $R = 8.3 \ J \ mol^{-1} \ K^{-1}$) (in $kJ$)

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