The amplitude of an oscillating simple pendulum is $10 \ cm$ and its period is $4 \ s$. Its speed $1 \ s$ after it passes its equilibrium position is ... $m/s$.

$A$ pendulum is swinging in an elevator. Its period will be greatest when the elevator is

$A$ simple pendulum executing $S.H.M.$ is falling freely along with its support. Then:

$A$ simple pendulum having length $\ell$ has a speed of $\sqrt{2g\ell}$ at the bottom-most point of its trajectory. Its motion will be:

The time period of a simple pendulum will be doubled if we:

$A$ light balloon filled with helium of density $\rho_{He}$ is tied to a light string of length $L.$ The string is tied to the ground forming an "inverted" simple pendulum (figure). If the balloon is displaced slightly from equilibrium as in figure and released, the period of the motion is. Take the density of air to be $\rho_{air}$. Assume the air applies a buoyant force on the balloon but does not otherwise affect its motion.