The angle between vectors (overrightarrow {A} | vedclass

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(B) The cross product of two vectors is anticommutative,which means $\overrightarrow {A} 	imes \overrightarrow {B} = -(\overrightarrow {B} 	imes \ov

Vedclass · Accepted Answer

$\pi$

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(B) The cross product of two vectors is anticommutative,which means $\overrightarrow {A} 	imes \overrightarrow {B} = -(\overrightarrow {B} 	imes \overrightarrow {A})$.This indicates that the vector $(\overrightarrow {A} 	imes \overrightarrow {B})$ is equal in magnitude but opposite in direction to the vector $(\overrightarrow {B} 	imes \overrightarrow {A})$.Since the two vectors are anti-parallel to each other,the angle between them is $180^{\circ}$ or $\pi$ radians.

The angle between vectors $(\overrightarrow {A} \times \overrightarrow {B})$ and $(\overrightarrow {B} \times \overrightarrow {A})$ is

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