The angular speed of a particle moving in a circular path is doubled. Then, the centripetal acceleration of the particle is

$A$ particle of mass $m$ is moving in a circular path of constant radius $r$ such that its tangential acceleration varies with time as $a_t = K^2rt^2$ ($K$ is a constant). Select the correct statement.

$A$ particle of mass $m$ is moving in a circular path of constant radius $r$ such that its centripetal acceleration is varying with time as $a_c = k^2rt^2$. The power delivered to the particle by the forces acting on it is $(k = \text{constant})$

$A$ particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\vec a = (4\hat i + 3\hat j)\ m/s^2$ and $\vec p = (8\hat i - 6\hat j)\ kg \cdot m/s$. The motion of the particle is

$A$ particle is in uniform circular motion. The equation of its trajectory is given by $(x-2)^2+y^2=25$,where $x$ and $y$ are in meters. The speed of the particle is $2 \text{ m/s}$. When the particle attains the lowest $y$ coordinate,the acceleration of the particle is (in $\text{m/s}^2$):

For a particle in a uniformly accelerated circular motion: