The approximate value of the mean deviation a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) First,we find the midpoints $(y_i)$ of the class intervals: $y_i$$1$$3$$5$$7$$9$$f_i$$1$$2$$3$$2$$1$ The mean $\bar{y}$ is calculated as: $\bar{y}

Vedclass · Accepted Answer

$1.78$

Vedclass · Answer

(D) First,we find the midpoints $(y_i)$ of the class intervals: $y_i$$1$$3$$5$$7$$9$$f_i$$1$$2$$3$$2$$1$ The mean $\bar{y}$ is calculated as: $\bar{y} = \frac{\sum f_i y_i}{\sum f_i} = \frac{(1 	imes 1) + (2 	imes 3) + (3 	imes 5) + (2 	imes 7) + (1 	imes 9)}{1+2+3+2+1} = \frac{1+6+15+14+9}{9} = \frac{45}{9} = 5$ The mean deviation about the mean is given by: $	ext{Mean Deviation} = \frac{\sum f_i |y_i - \bar{y}|}{\sum f_i} = \frac{1|1-5| + 2|3-5| + 3|5-5| + 2|7-5| + 1|9-5|}{9}$ $= \frac{1(4) + 2(2) + 3(0) + 2(2) + 1(4)}{9} = \frac{4+4+0+4+4}{9} = \frac{16}{9} \approx 1.78$

Class Interval	$0-2$	$2-4$	$4-6$	$6-8$	$8-10$
Frequency	$1$	$2$	$3$	$2$	$1$

Class interval	$0$-$10$	$10$-$20$	$20$-$30$	$30$-$40$	$40$-$50$	$50$-$60$	$60$-$70$
Frequency	$4$	$6$	$16$	$28$	$16$	$6$	$4$

Class Interval	$0-4$	$4-8$	$8-12$	$12-16$
Frequency	$4$	$3$	$2$	$1$

The approximate value of the mean deviation about the mean for the following data is
Class Interval $0-2$ $2-4$ $4-6$ $6-8$ $8-10$
Frequency $1$ $2$ $3$ $2$ $1$

Similar Questions

Find the mean deviation about the mean for the following data:
Class interval $0$-$10$ $10$-$20$ $20$-$30$ $30$-$40$ $40$-$50$ $50$-$60$ $60$-$70$
Frequency $4$ $6$ $16$ $28$ $16$ $6$ $4$

If the mean deviation about the median of $x, 2x, 3x, 4x, 5x, 6x, 7x, 8x, 9x, 10x$ is $30$,then $|x|$ equals:

The mean deviation about the mean for the following data is

Class Interval $0-4$ $4-8$ $8-12$ $12-16$

Frequency $4$ $3$ $2$ $1$

The mean deviation from the median for the following data is
$x_i$ $2, 9, 8, 3, 5, 7$
$f_i$ $5, 3, 1, 6, 6, 1$

The mean and variance of $10$ observations are $9$ and $34.2$, respectively. If $8$ of these observations are $2, 3, 5, 10, 11, 13, 15, 21$, then the mean deviation about the median of all the $10$ observations is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The approximate value of the mean deviation about the mean for the following data is Class Interval$0-2$$2-4$$4-6$$6-8$$8-10$Frequency$1$$2$$3$$2$$1$