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Silver atom has completely filled $d$ orbitals $\left(4d^{10}\right)$ in its ground state. How can you say that it is a transition element?
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View SolutionThe number of unpaired electrons in $Zn^{2+}$ is
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View SolutionIron $(Fe)$ is classified as:
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View SolutionMatch the following atoms/ions with their correct electronic configurations:
Atom/Ion Electronic Configuration $(1) \ Cu$ $(A) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}$ $(2) \ Cu^{2+}$ $(B) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^2$ $(3) \ Zn^{2+}$ $(C) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^1$ $(4) \ Cr^{3+}$ $(D) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^9$ $(E) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^3$
| Atom/Ion | Electronic Configuration |
| $(1) \ Cu$ | $(A) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}$ |
| $(2) \ Cu^{2+}$ | $(B) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^2$ |
| $(3) \ Zn^{2+}$ | $(C) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^{10}, 4s^1$ |
| $(4) \ Cr^{3+}$ | $(D) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^9$ |
| $(E) 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^3$ |
Medium
View SolutionIdentify the metal that forms colourless compounds.
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