(C) Let $N_A$ be the Avogadro number.Number of moles of $A = x/40$.Number of atoms of $A = (x/40) \times N_A = y$.Thus,$x = (40 \times y) / N_A$.Numbe

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(C) Let $N_A$ be the Avogadro number.Number of moles of $A = x/40$.Number of atoms of $A = (x/40) \times N_A = y$.Thus,$x = (40 \times y) / N_A$.Number of moles of $B = 2x/80 = x/40$.Number of atoms of $B = (x/40) \times N_A$.Substituting the value of $x$,we get: $((40 \times y) / (40 \times N_A)) \times N_A = y$.Therefore,the number of atoms in $2x \ g$ of $B$ is $y$.