The audio signal used to modulate 60 sin(2pi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The carrier wave is given by $E_c(t) = 60 \sin(2\pi 	imes 10^6 t)$,so the amplitude of the carrier wave is $E_c = 60$.The modulating signal is gi

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(C) The carrier wave is given by $E_c(t) = 60 \sin(2\pi 	imes 10^6 t)$,so the amplitude of the carrier wave is $E_c = 60$.The modulating signal is given by $E_m(t) = 15 \sin(300\pi t)$,so the amplitude of the modulating signal is $E_m = 15$.The modulation index (or depth of modulation) $m_a$ is defined as the ratio of the amplitude of the modulating signal to the amplitude of the carrier wave:$m_a = \frac{E_m}{E_c} = \frac{15}{60} = 0.25$.To express this as a percentage,we multiply by $100$:$m_a = 0.25 	imes 100 = 25\%$.

The audio signal used to modulate $60 \sin(2\pi \times 10^6 t)$ is $15 \sin(300\pi t)$. The depth of modulation is.......$\%$

Similar Questions

$A$ carrier signal of frequency $1.5 MHz$ has an amplitude of $50 V$. It is amplitude modulated by a modulating wave of frequency $10 kHz$ with a modulation index of $50 \%$. What are the frequencies of the $LSB$ and $USB$?

If $E_c$ and $E_m$ are peak values of carrier and modulating signals,respectively,then for $100 \%$ modulation,

$A$ $TV$ tower has a height of $160 \,m$. Its coverage range is nearly (Earth's radius,$R_e = 6400 \,km$):

At a particular station,the $TV$ transmission tower has a height of $100\,m$. To triple its coverage range,the height of the tower should be increased to ......$m$.

$A$ receiving station on the ground is receiving a signal of frequency $5 \ MHz$ from a transmitter. Then the signal can come via

Vedclass Test Series

Exam Paper Generator

Online Exam Module