The average age of students of a class is 15. | vedclass

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(B) Let the number of boys be $m$ and the number of girls be $n$.Given that the average age of boys is $16.4 	ext{ years}$ and the average age of gir

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$2: 3$

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(B) Let the number of boys be $m$ and the number of girls be $n$.Given that the average age of boys is $16.4 	ext{ years}$ and the average age of girls is $15.4 	ext{ years}$.The total average age of the class is $15.8 	ext{ years}$.Using the weighted average formula:$\frac{m 	imes 16.4 + n 	imes 15.4}{m + n} = 15.8$$16.4m + 15.4n = 15.8(m + n)$$16.4m + 15.4n = 15.8m + 15.8n$Rearranging the terms to group $m$ and $n$:$16.4m - 15.8m = 15.8n - 15.4n$$0.6m = 0.4n$$\frac{m}{n} = \frac{0.4}{0.6} = \frac{2}{3}$Thus,the ratio of the number of boys to the number of girls is $2: 3$.

The average age of students of a class is $15.8 \text{ years}$. The average age of boys in the class is $16.4 \text{ years}$ and that of the girls is $15.4 \text{ years}$. The ratio of the number of boys to the number of girls in the class is:

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