The average of 11 numbers is 10.9. If the ave | vedclass

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(C) The sum of all $11$ numbers is $11 	imes 10.9 = 119.9$.The sum of the first $6$ numbers is $6 	imes 10.5 = 63$.The sum of the last $6$ numbers i

Vedclass · Accepted Answer

$11.5$

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(C) The sum of all $11$ numbers is $11 	imes 10.9 = 119.9$.The sum of the first $6$ numbers is $6 	imes 10.5 = 63$.The sum of the last $6$ numbers is $6 	imes 11.4 = 68.4$.The sum of the first $6$ and last $6$ numbers includes the sixth number twice. Therefore, the sixth number is calculated as:$	ext{Sixth number} = (	ext{Sum of first } 6) + (	ext{Sum of last } 6) - (	ext{Sum of all } 11)$$	ext{Sixth number} = 63 + 68.4 - 119.9 = 131.4 - 119.9 = 11.5$.Thus, the middle number is $11.5$.

The average of $11$ numbers is $10.9$. If the average of the first six is $10.5$ and the average of the last six is $11.4$, find the middle (sixth) number.

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