The average of three consecutive odd numbers | vedclass

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Question

(C) Let the three consecutive odd numbers be $x$,$x+2$,and $x+4$.The average of these three numbers is $\frac{x + (x+2) + (x+4)}{3} = \frac{3x+6}{3} =

Vedclass · Accepted Answer

$19$

Vedclass · Answer

(C) Let the three consecutive odd numbers be $x$,$x+2$,and $x+4$.The average of these three numbers is $\frac{x + (x+2) + (x+4)}{3} = \frac{3x+6}{3} = x+2$.According to the problem,the average is $12$ more than one-third of the first number $(x)$:$x+2 = \frac{x}{3} + 12$Multiply the entire equation by $3$ to clear the fraction:$3(x+2) = x + 36$$3x + 6 = x + 36$Subtract $x$ from both sides:$2x + 6 = 36$Subtract $6$ from both sides:$2x = 30$$x = 15$The three numbers are $15$,$17$,and $19$.Therefore,the last of the three numbers is $19$.

The average of three consecutive odd numbers is $12$ more than one-third of the first of these numbers. What is the last of the three numbers?

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