The average weight of 4 men A, B, C, and D is | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. Initial sum of weights of $A, B, C, D = 4 	imes 67 = 268 \, kg.$$2$. After including $E,$ total men = $5,$ and new average = $67 - 2 = 65 \,

Vedclass · Accepted Answer

$66$

Vedclass · Answer

(B) $1$. Initial sum of weights of $A, B, C, D = 4 	imes 67 = 268 \, kg.$$2$. After including $E,$ total men = $5,$ and new average = $67 - 2 = 65 \, kg.$$3$. Total weight of $5$ men $(A+B+C+D+E) = 5 	imes 65 = 325 \, kg.$$4$. Weight of $E = 325 - 268 = 57 \, kg.$$5$. Weight of $F = E + 4 = 57 + 4 = 61 \, kg.$$6$. After replacing $A$ with $F,$ the new average weight is $64 \, kg.$$7$. Total weight of $5$ men $(F+B+C+D+E) = 5 	imes 64 = 320 \, kg.$$8$. Since $(A+B+C+D+E) = 325,$ we have $(B+C+D+E) = 325 - A.$$9$. Substituting this into the new total: $F + (325 - A) = 320.$$10$. $61 + 325 - A = 320 \implies 386 - A = 320 \implies A = 66 \, kg.$

Similar Questions

The average of $5$ consecutive integers starting with $m$ is $n$. What is the average of $6$ consecutive integers starting with $(m+2)?$

The average of $50$ numbers is $38$. If two numbers,namely $45$ and $55$,are discarded,the average of the remaining numbers is

If the mean of $5$ observations $x, x+2, x+4, x+6$ and $x+8$ is $11,$ then the mean of the last three observations is

Out of $9$ persons,$8$ persons spent $Rs. 30$ each for their meals. The ninth one spent $Rs. 20$ more than the average expenditure of all the nine. The total money spent by all of them was (in $Rs.$)

The average weight of a class of $24$ students is $35 \, kg$. If the weight of the teacher is included, the average weight increases by $400 \, g$. The weight of the teacher is (in $kg$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module