The barrel of a fountain pen,cylindrical in s | vedclass

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(D) Given,length of the barrel of a fountain pen $h = 7 \, cm$.Diameter $d = 5 \, mm = 0.5 \, cm$,so radius $r = 0.25 \, cm$.Volume of the cylindrical

Vedclass · Accepted Answer

$480000$

Vedclass · Answer

(D) Given,length of the barrel of a fountain pen $h = 7 \, cm$.Diameter $d = 5 \, mm = 0.5 \, cm$,so radius $r = 0.25 \, cm$.Volume of the cylindrical barrel $V = \pi r^2 h = \frac{22}{7} 	imes (0.25)^2 	imes 7 = 22 	imes 0.0625 = 1.375 \, cm^3$.It is given that $1.375 \, cm^3$ of ink writes $3300$ words.Volume of ink in the bottle $= \frac{1}{5} \, L = \frac{1}{5} 	imes 1000 \, cm^3 = 200 \, cm^3$.Number of words written with $200 \, cm^3$ of ink $= \frac{3300}{1.375} 	imes 200$.$= \frac{3300 	imes 200}{1.375} = \frac{660000}{1.375} = 480000$ words.

The barrel of a fountain pen,cylindrical in shape,is $7 \, cm$ long and $5 \, mm$ in diameter. $A$ full barrel of ink in the pen is used up on writing $3300$ words on an average. How many words can be written in a bottle of ink containing one-fifth of a litre?

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