The base of a cone with radius 5 , cm and hei | vedclass

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(D) The article consists of a cone placed on a hemisphere. The total surface area is the sum of the curved surface area of the cone and the curved sur

Vedclass · Accepted Answer

$361.1$

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(D) The article consists of a cone placed on a hemisphere. The total surface area is the sum of the curved surface area of the cone and the curved surface area of the hemisphere.$1$. Slant height of the cone $(l)$: $l = \sqrt{r^2 + h^2} = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \, cm$.$2$. Curved surface area of the cone $(CSA_{cone})$: $\pi rl = 3.14 	imes 5 	imes 13 = 204.1 \, cm^2$.$3$. Curved surface area of the hemisphere $(CSA_{hemi})$: $2\pi r^2 = 2 	imes 3.14 	imes 5^2 = 2 	imes 3.14 	imes 25 = 157 \, cm^2$.$4$. Total surface area: $CSA_{cone} + CSA_{hemi} = 204.1 + 157 = 361.1 \, cm^2$.

The base of a cone with radius $5 \, cm$ and height $12 \, cm$ is hemispherical. Find the total surface area of the article. $(\pi = 3.14)$ (in $cm^2$)

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