The basicity of the hydroxides of the followi | vedclass

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Question

(C) The basicity of alkali metal hydroxides depends on the ease with which the $OH^-$ ion can be released. As we move down the group from $Li$ to $Cs$

Vedclass · Accepted Answer

$CsOH > RbOH > NaOH > LiOH$

Vedclass · Answer

(C) The basicity of alkali metal hydroxides depends on the ease with which the $OH^-$ ion can be released. As we move down the group from $Li$ to $Cs$,the atomic size increases. Due to the increase in size,the bond length between the metal cation $(M^+)$ and the hydroxide ion $(OH^-)$ increases,which decreases the bond strength. Consequently,the $M-OH$ bond becomes easier to break,making the hydroxide more basic. Therefore,the order of basicity is $LiOH < NaOH < KOH < RbOH < CsOH$.

The basicity of the hydroxides of the following alkali metals is of the order:

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