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(B) The nuclear fusion reaction is given by $2X \rightarrow Y + Q$.The binding energy of the initial state is the sum of the binding energies of the t

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$Q = E_2 - 2E_1$

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(B) The nuclear fusion reaction is given by $2X ightarrow Y + Q$.The binding energy of the initial state is the sum of the binding energies of the two $X$ nuclei, which is $2E_1$.The binding energy of the final state is the binding energy of the $Y$ nucleus, which is $E_2$.Energy released $Q$ in a nuclear reaction is equal to the difference between the final binding energy and the initial binding energy.Therefore, $Q = (	ext{Final Binding Energy}) - (	ext{Initial Binding Energy})$.$Q = E_2 - 2E_1$.

The binding energies of nuclei $X$ and $Y$ are $E_1$ and $E_2$ respectively. Two atoms of $X$ fuse to give one atom of $Y$ and an energy $Q$ is released. Then:

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