The binding energy per nucleon for C^{12} is | vedclass

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(A) The nuclear reaction for removing a neutron from $C^{13}$ is given by: $C^{13} + 	ext{Energy} ightarrow C^{12} + n$.The total binding energy of

Vedclass · Accepted Answer

$5.34$

Vedclass · Answer

(A) The nuclear reaction for removing a neutron from $C^{13}$ is given by: $C^{13} + 	ext{Energy} ightarrow C^{12} + n$.The total binding energy of a nucleus is calculated as the product of the number of nucleons $(A)$ and the binding energy per nucleon $(BE/A)$.Total binding energy of $C^{13} = 13 	imes 7.5 	ext{ MeV} = 97.5 	ext{ MeV}$.Total binding energy of $C^{12} = 12 	imes 7.68 	ext{ MeV} = 92.16 	ext{ MeV}$.The energy required to remove a neutron is the difference between the total binding energy of $C^{13}$ and $C^{12}$:$	ext{Energy} = (13 	imes 7.5) - (12 	imes 7.68) 	ext{ MeV}$.$	ext{Energy} = 97.5 - 92.16 = 5.34 	ext{ MeV}$.

The binding energy per nucleon for $C^{12}$ is $7.68 \text{ MeV}$ and that for $C^{13}$ is $7.5 \text{ MeV}$. The energy required to remove a neutron from $C^{13}$ is ......... $\text{MeV}$.

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