The bob of a simple pendulum (mass m and leng | vedclass

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(C) The potential energy $(P.E.)$ of the bob at the horizontal position $A$ is $mgl$,taking the lowest point $B$ as the reference level.As the bob fal

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$mgl$

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(C) The potential energy $(P.E.)$ of the bob at the horizontal position $A$ is $mgl$,taking the lowest point $B$ as the reference level.As the bob falls to point $B$,this potential energy is converted into kinetic energy $(K.E.)$.Thus,the kinetic energy of the bob at point $B$ just before the collision is $K.E. = mgl$.Since the collision between the bob and the block is elastic and they have the same mass $(m)$,the velocities are exchanged during the collision.The bob comes to rest at point $B$,and the entire kinetic energy is transferred to the block.Therefore,the kinetic energy of the block after the collision is $mgl$.

The bob of a simple pendulum (mass $m$ and length $l$) is dropped from a horizontal position. It strikes a block of the same mass $m$ placed on a horizontal frictionless table. The collision is elastic. The kinetic energy of the block after the collision will be

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