The boiling point of water at 1 atm is 100^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The process of vaporization is non-spontaneous below the boiling point at $1 \ atm$ pressure. For any process,the spontaneity is determined by the

Vedclass · Accepted Answer

$\Delta G_{	ext{vap}}^{\circ} > 0$

Vedclass · Answer

(A) The process of vaporization is non-spontaneous below the boiling point at $1 \ atm$ pressure. For any process,the spontaneity is determined by the Gibbs free energy change,$\Delta G = \Delta H - T \Delta S$. At the boiling point $(T_{b} = 373 \ K)$,the system is at equilibrium,so $\Delta G = 0$,which implies $\Delta S = \Delta H / T_{b}$. For vaporization,$\Delta H > 0$ and $\Delta S > 0$. At $T = 75^{\circ} C = 348 \ K$,since $T Therefore,$\Delta G = \Delta H - T \Delta S > 0$. Since $\Delta G > 0$,the process is non-spontaneous at $75^{\circ} C$.

The boiling point of water at $1 \ atm$ is $100^{\circ} C$. Which among the following is true for vaporisation of water at $75^{\circ} C$?

Similar Questions

$A$ reaction has both $\Delta H$ and $\Delta S$ negative. The rate of reaction

The temperature in $K$ at which $\Delta G = 0$, for a given reaction with $\Delta H = -20.5 \ kJ \ mol^{-1}$ and $\Delta S = -50.0 \ J \ K^{-1} \ mol^{-1}$ is:

Which of the following processes will never be a spontaneous process?

The value of ${\left[ {\frac{dG}{dT}} \right]_P}$ is ....

$2 \, mol$ of zinc is dissolved in $HCl$ at $25 \, ^\circ C$. The work done in an open vessel is: (in $, kJ$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module