The bond dissociation energy of the C-H bond | vedclass

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Question

(C) The bond dissociation energy is inversely proportional to the stability of the free radical formed after the homolytic cleavage of the $C-H$ bond.

Vedclass · Accepted Answer

$IV > I > II > III$

Vedclass · Answer

(C) The bond dissociation energy is inversely proportional to the stability of the free radical formed after the homolytic cleavage of the $C-H$ bond.$1$. The radicals formed are:$(I)\ CH_3^{\bullet}$ (Methyl radical)$(II)\ CH_3-CH_2^{\bullet}$ (Primary ethyl radical)$(III)\ CH_2=CH-CH_2^{\bullet}$ (Allyl radical,resonance stabilized)$(IV)\ C_6H_5^{\bullet}$ (Phenyl radical,$sp^2$ hybridized carbon)$2$. Stability order of radicals: $(III) > (II) > (I) > (IV)$.$3$. Since bond dissociation energy is inversely proportional to radical stability,the order of energy required is: $(IV) > (I) > (II) > (III)$.

The bond dissociation energy of the $C-H$ bond for the compounds: $(I)\ CH_3-H, (II)\ CH_3-CH_2-H, (III)\ CH_2=CH-CH_2-H, (IV)\ C_6H_5-H$ follows the order:

Similar Questions

Which of the following carbocations is most stable?
$A) (CH_3)_2CH-CH^+-CH_3$
$B) (CH_3)_2C^+-CH_2CH_3$

Compare the stability of the following free radicals:
$(1)$ $CH_3 - \dot{CH} - CH_3$
$(2)$ $C_6H_5 - \dot{CH_2}$
$(3)$ $\dot{CH_2} - CH(CH_3)_2$
$(4)$ $\dot{CH_2} - CH_3$

Which of the following are secondary radicals?
$(1) \ CH_3 - \dot{C}H - C_2H_5$
$(2) \ CH_2 = \dot{C} - CH_3$
$(3) \ CH_2 = CH - \dot{C}H_2$
$(4) \ (CH_3)_2 \dot{C}H$

Consider the following carbocations. What is the relative stability order of these carbocations?
$(1)$ $CH_3O-C_6H_4-CH_2^+$
$(2)$ $C_6H_5-CH_2^+$
$(3)$ $CH_3-C_6H_4-CH_2^+$

The stability of the following carbocations follows the order:

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