The bond energy of $Cl_2, Br_2$ and $I_2$ follows the order:

Which product is formed when fluorine reacts with hot and concentrated sodium hydroxide?

Which of the following is used to prepare $Cl_2$ gas at room temperature from concentrated $HCl$?

$HBr$ and $HI$ reduce sulphuric acid,$HCl$ can reduce $KMnO_4$ and $HF$ can reduce:

Fluorine is a stronger oxidising agent than chlorine because :
$(a)$ $F-F$ bond has a low enthalpy of dissociation.
$(b)$ Fluoride ion $(F^{-})$ has high hydration enthalpy.
$(c)$ Electron gain enthalpy of fluorine is less negative than chlorine.
$(d)$ Fluorine has a very small size.
Choose the most appropriate answer from the options given :

The strongest reducing agent among the following is: