The bond order and the magnetic characteristi | vedclass

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Question

(A) According to Molecular Orbital Theory $(MOT)$: The total number of electrons in $CN^{-}$ is $6 + 7 + 1 = 14$. The electronic configuration is: $\s

Vedclass · Accepted Answer

$3,$ diamagnetic

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(A) According to Molecular Orbital Theory $(MOT)$: The total number of electrons in $CN^{-}$ is $6 + 7 + 1 = 14$. The electronic configuration is: $\sigma_{1s}^{2}, \sigma_{1s}^{*2}, \sigma_{2s}^{2}, \sigma_{2s}^{*2}, \pi_{2p_{x}}^{2} = \pi_{2p_{y}}^{2}, \sigma_{2p_{z}}^{2}$. Bond order $= \frac{1}{2}(N_b - N_a) = \frac{1}{2}(10 - 4) = 3$. Since all electrons are paired,$CN^{-}$ is diamagnetic.

The bond order and the magnetic characteristics of $CN^{-}$ are

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