The bond order in N_2^+ ion is | vedclass

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(C) The total number of electrons in $N_2^+$ is $7 + 7 - 1 = 13$. According to Molecular Orbital Theory,the electronic configuration is $\sigma 1s^2,

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$2.5$

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(C) The total number of electrons in $N_2^+$ is $7 + 7 - 1 = 13$. According to Molecular Orbital Theory,the electronic configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2 = \pi 2p_y^2, \sigma 2p_z^1$. Number of bonding electrons $(N_b)$ = $2 + 2 + 2 + 2 + 1 = 9$. Number of antibonding electrons $(N_a)$ = $2 + 2 = 4$. Bond Order $(B.O.)$ = $\frac{N_b - N_a}{2} = \frac{9 - 4}{2} = \frac{5}{2} = 2.5$.

The bond order in $N_2^+$ ion is

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