The Boolean expression for a two-input Ex-OR | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The truth table for an Ex-$OR$ gate is as follows:| Input $A$ | Input $B$ | Output $Y = A \oplus B$ || :--- | :--- | :--- || $0$ | $0$ | $0$ || $0

Vedclass · Accepted Answer

$Y=(\bar{A} \cdot B)+(A \cdot \bar{B})$

Vedclass · Answer

(C) The truth table for an Ex-$OR$ gate is as follows:| Input $A$ | Input $B$ | Output $Y = A \oplus B$ || :--- | :--- | :--- || $0$ | $0$ | $0$ || $0$ | $1$ | $1$ || $1$ | $0$ | $1$ || $1$ | $1$ | $0$ |The output equation for an Ex-$OR$ gate is $Y = A \oplus B = (\bar{A} \cdot B) + (A \cdot \bar{B})$.Key points to remember:$(1)$ The output is low $(0)$ when both inputs are the same.$(2)$ The output is high $(1)$ when both inputs are different.

The Boolean expression for a two-input Ex-$OR$ gate is (where $A$ and $B$ are inputs,and $Y$ is the output):

Similar Questions

The output $Y$ of the given logic circuit is:

In the following digital circuit,what will be the output at $Z$ when the inputs $(A, B)$ are $(1,0), (0,0), (1,1), (0,1)$?

In the circuit shown, inputs $A$ and $B$ are in states $1$ and $0$ respectively. What is the only possible stable state of the outputs $X$ and $Y$?

Two $4-$bit binary numbers, $A = 1101$ and $B = 1010$, are given as inputs to the logic circuit shown in the figure below. The output $(Y)$ will be:

To get the truth table shown from the following logic circuit, the gate $G$ should be

Vedclass Test Series

Exam Paper Generator

Online Exam Module