The brown ring test for $NO_2^-$ and $NO_3^-$ is due to the formation of a complex ion with the formula:

  • A
    $[Fe(H_2O)_6]^{2+}$
  • B
    $[Fe(NO)(CN)_5]^{2+}$
  • C
    $[Fe(H_2O)_5(NO)]^{2+}$
  • D
    $[Fe(H_2O)(NO)_5]^{2+}$

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$A$ solution containing $2.675 \ g$ of $CoCl_3 \cdot 6 NH_3$ (molar mass $= 267.5 \ g \ mol^{-1}$) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of $AgNO_3$ to give $4.78 \ g$ of $AgCl$ (molar mass $= 143.5 \ g \ mol^{-1}$). The formula of the complex is
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