(A) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given:Capacitance $C = 4 \times 10^{-6} \, F$Potential $V = 100 \

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(A) The energy stored in a capacitor is given by the formula $U = \frac{1}{2} C V^2$.Given:Capacitance $C = 4 \times 10^{-6} \, F$Potential $V = 100 \, V$Substituting the values into the formula:$U = \frac{1}{2} \times (4 \times 10^{-6}) \times (100)^2$$U = \frac{1}{2} \times 4 \times 10^{-6} \times 10000$$U = 2 \times 10^{-6} \times 10^4$$U = 2 \times 10^{-2} \, J$$U = 0.02 \, J$Therefore,the energy released is $0.02 \, J$.

Class 12 Physics Electric Potential and Capacitance Energy Stored in a Capacitor

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The capacity of a capacitor is $4 \times 10^{-6} \, F$ and its potential is $100 \, V$. The energy released on discharging it fully will be ....... $J$.

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AIIMS 1984 All AIIMS

A
$0.02$
B
$0.04$
C
$0.025$
D
$0.05$

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Electric Potential and Capacitance

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Energy Stored in a Capacitor

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MediumAIIMS 2019

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The capacity of a capacitor is $4 \times 10^{-6} \, F$ and its potential is $100 \, V$. The energy released on discharging it fully will be ....... $J$.

Similar Questions

Given $C_1 = 2\ \mu F$,$C_2 = 6\ \mu F$,and $C_3 = 4\ \mu F$. What is the total energy of the system?

If the charge on the capacitor is increased by $2 \text{ C}$, the energy stored in it increases by $21 \%$. The original charge on the capacitor is (in $\text{ C}$)

What is the total energy of the given system in $joules$?

$A$ $5.0 \mu F$ capacitor is charged to a potential difference of $800 V$ and discharged through a conductor. The energy (in $J$) given to the conductor during the discharge is:

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