The cell reaction of the galvanic cell Cu_{(s | vedclass

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Question

(B) In a galvanic cell representation,the left side represents the anode where oxidation occurs,and the right side represents the cathode where reduct

Vedclass · Accepted Answer

$Cu + Hg^{2+} 	o Cu^{2+} + Hg$

Vedclass · Answer

(B) In a galvanic cell representation,the left side represents the anode where oxidation occurs,and the right side represents the cathode where reduction occurs.Given cell: $Cu_{(s)} | Cu^{2+}_{(aq)} || Hg^{2+}_{(aq)} | Hg_{(l)}$Anode (Oxidation): $Cu_{(s)} 	o Cu^{2+}_{(aq)} + 2e^-$Cathode (Reduction): $Hg^{2+}_{(aq)} + 2e^- 	o Hg_{(l)}$Adding these two half-reactions,we get the overall cell reaction:$Cu_{(s)} + Hg^{2+}_{(aq)} 	o Cu^{2+}_{(aq)} + Hg_{(l)}$Therefore,the correct option is $B$.

The cell reaction of the galvanic cell $Cu_{(s)} | Cu^{2+}_{(aq)} || Hg^{2+}_{(aq)} | Hg_{(l)}$ is

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