The chance of throwing a total of 7 or 12 wit | vedclass

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(D) Total number of outcomes when throwing $2$ dice is $6 	imes 6 = 36$.For a sum of $7$,the favourable outcomes are $(1, 6), (2, 5), (3, 4), (4, 3),

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$\frac{7}{36}$

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(D) Total number of outcomes when throwing $2$ dice is $6 	imes 6 = 36$.For a sum of $7$,the favourable outcomes are $(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)$,which is $6$ outcomes.For a sum of $12$,the only favourable outcome is $(6, 6)$,which is $1$ outcome.Since these events are mutually exclusive,the total probability is $\frac{6}{36} + \frac{1}{36} = \frac{7}{36}$.

The chance of throwing a total of $7$ or $12$ with $2$ dice is:

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