The charges on two spheres are +7,mu C and -5 | vedclass

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(A) According to Coulomb's Law,the force between two point charges is given by $F = k \frac{q_1 q_2}{r^2}$.Initially,the charges are $q_1 = +7\,\mu C$

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$F$

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(A) According to Coulomb's Law,the force between two point charges is given by $F = k \frac{q_1 q_2}{r^2}$.Initially,the charges are $q_1 = +7\,\mu C$ and $q_2 = -5\,\mu C$. The magnitude of the force is $F = k \frac{(7)(5)}{r^2} = k \frac{35}{r^2}$.When an additional charge of $-2\,\mu C$ is added to each sphere,the new charges become:$q_1' = +7\,\mu C - 2\,\mu C = +5\,\mu C$$q_2' = -5\,\mu C - 2\,\mu C = -7\,\mu C$The new force $F'$ is given by $F' = k \frac{|q_1' q_2'|}{r^2} = k \frac{|(5)(-7)|}{r^2} = k \frac{35}{r^2}$.Comparing the two expressions,we find that $F' = F$.

The charges on two spheres are $+7\,\mu C$ and $-5\,\mu C$ respectively. They experience a force $F$. If each of them is given an additional charge of $-2\,\mu C$,the new force of attraction will be

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