The chemical formula of the oxide of an eleme | vedclass

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(B) $1$. In the oxide $X_2O_5$,the valency of oxygen is $2$. $2$. Let the valency of element $X$ be $v$. $3$. According to the criss-cross method for

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$XCl_5$

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(B) $1$. In the oxide $X_2O_5$,the valency of oxygen is $2$. $2$. Let the valency of element $X$ be $v$. $3$. According to the criss-cross method for $X_2O_5$,the valency of $X$ is $5$ (since $2 	imes v = 5 	imes 2$,so $v = 5$). $4$. Chlorine $(Cl)$ has a valency of $1$. $5$. To write the formula of the chloride of $X$,we place the valency of $X$ $(5)$ under $Cl$ and the valency of $Cl$ $(1)$ under $X$. $6$. Thus,the chemical formula is $X_1Cl_5$,which is written as $XCl_5$.

Species property	$H_2O$	$CO_2$	$Na$ atom	$MgCl_2$
No. of moles	$2$	-	-	$0.5$
No. of particles	-	$3.011 \times 10^{23}$	-	-
Mass	$36 \, g$	-	$115 \, g$	-

The chemical formula of the oxide of an element $X$ is $X_2O_5$. Write the chemical formula of its chloride.

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Fill in the missing data in the Table.
Species property $H_2O$ $CO_2$ $Na$ atom $MgCl_2$
No. of moles $2$ - - $0.5$
No. of particles - $3.011 \times 10^{23}$ - -
Mass $36 \, g$ - $115 \, g$ -

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