The coagulation of 100 , mL of a colloidal so | vedclass

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(B) The gold number is defined as the minimum amount of a protective colloid in $mg$ that is required to prevent the coagulation of $10 \, mL$ of a st

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(B) The gold number is defined as the minimum amount of a protective colloid in $mg$ that is required to prevent the coagulation of $10 \, mL$ of a standard gold sol when $1 \, mL$ of $10 \% \ NaCl$ solution is added to it.Given that $0.25 \, g$ of substance '$X$' prevents coagulation in $100 \, mL$ of gold sol.Convert the mass of '$X$' to $mg$: $0.25 \, g = 0.25 	imes 1000 \, mg = 250 \, mg$.Since $250 \, mg$ of '$X$' is required for $100 \, mL$ of gold sol,the amount required for $10 \, mL$ of gold sol is:$\frac{250 \, mg}{100 \, mL} 	imes 10 \, mL = 25 \, mg$.Therefore,the gold number of '$X$' is $25$.

The coagulation of $100 \, mL$ of a colloidal sol of gold is completely prevented by the addition of $0.25 \, g$ of a substance '$X$' to it before adding $10 \, mL$ of $1 \% \ NaCl$ solution. The gold number of '$X$' is:

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