The coefficient of performance of a refrigera | vedclass

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(B) The coefficient of performance $(COP)$ of a refrigerator is given by the formula:$COP = \frac{T_L}{T_H - T_L}$where $T_L$ is the temperature insid

Vedclass · Accepted Answer

$31$

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(B) The coefficient of performance $(COP)$ of a refrigerator is given by the formula:$COP = \frac{T_L}{T_H - T_L}$where $T_L$ is the temperature inside the freezer and $T_H$ is the temperature of the surroundings.First,convert the temperature from Celsius to Kelvin:$T_L = -20 + 273 = 253 \, K$.Given $COP = 5$,substitute the values into the formula:$5 = \frac{253}{T_H - 253}$$5(T_H - 253) = 253$$5T_H - 1265 = 253$$5T_H = 1518$$T_H = 303.6 \, K$.Now,convert the temperature back to Celsius:$T_H (^{\circ}C) = 303.6 - 273 = 30.6 \, ^{\circ}C \approx 31 \, ^{\circ}C$.

The coefficient of performance of a refrigerator is $5$. If the temperature inside the freezer is $-20\,^{\circ}C$,the temperature of the surroundings to which it rejects heat is ....... $^{\circ}C$.

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