The coefficient of variation of 9, 3, 11, 5, | vedclass

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(C) The given data set is $9, 3, 11, 5, 7$. First,calculate the mean $(\bar{x})$: $\bar{x} = \frac{9+3+11+5+7}{5} = \frac{35}{5} = 7$. Next,calculate

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$\frac{200 \sqrt{2}}{7}$

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(C) The given data set is $9, 3, 11, 5, 7$. First,calculate the mean $(\bar{x})$: $\bar{x} = \frac{9+3+11+5+7}{5} = \frac{35}{5} = 7$. Next,calculate the variance $(\sigma^2)$: $\sigma^2 = \frac{1}{n} \sum (x_i - \bar{x})^2 = \frac{(9-7)^2 + (3-7)^2 + (11-7)^2 + (5-7)^2 + (7-7)^2}{5}$ $= \frac{2^2 + (-4)^2 + 4^2 + (-2)^2 + 0^2}{5} = \frac{4 + 16 + 16 + 4 + 0}{5} = \frac{40}{5} = 8$. The standard deviation $(\sigma)$ is $\sqrt{8} = 2\sqrt{2}$. The coefficient of variation $(CV)$ is given by: $CV = \frac{\sigma}{\bar{x}} 	imes 100 = \frac{2\sqrt{2}}{7} 	imes 100 = \frac{200\sqrt{2}}{7}$.

The coefficient of variation of $9, 3, 11, 5, 7$ is

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