The coefficient of variation of the first 5 p | vedclass

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(A) The first $5$ prime numbers are $2, 3, 5, 7, 11$. The mean $\bar{x} = \frac{2+3+5+7+11}{5} = \frac{28}{5} = 5.6$. The sum of squares $\Sigma x_i^2

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$\frac{400}{7}$

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(A) The first $5$ prime numbers are $2, 3, 5, 7, 11$. The mean $\bar{x} = \frac{2+3+5+7+11}{5} = \frac{28}{5} = 5.6$. The sum of squares $\Sigma x_i^2 = 2^2 + 3^2 + 5^2 + 7^2 + 11^2 = 4 + 9 + 25 + 49 + 121 = 208$. The standard deviation $\sigma = \sqrt{\frac{\Sigma x_i^2}{n} - (\bar{x})^2} = \sqrt{\frac{208}{5} - (\frac{28}{5})^2} = \sqrt{\frac{1040 - 784}{25}} = \sqrt{\frac{256}{25}} = \frac{16}{5} = 3.2$. The coefficient of variation $C.V. = \frac{\sigma}{\bar{x}} 	imes 100 = \frac{16/5}{28/5} 	imes 100 = \frac{16}{28} 	imes 100 = \frac{4}{7} 	imes 100 = \frac{400}{7}$.

The coefficient of variation of the first $5$ prime numbers is

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