The coefficients of apparent expansion of a l | vedclass

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(D) The coefficient of real expansion of a liquid is constant and is given by the relation: $\gamma_{	ext{real}} = \gamma_{	ext{app}} + \gamma_{	ex

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$\frac{\gamma_1-\gamma_2}{3}+\alpha$

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(D) The coefficient of real expansion of a liquid is constant and is given by the relation: $\gamma_{	ext{real}} = \gamma_{	ext{app}} + \gamma_{	ext{vessel}}$.For vessel $A$,the coefficient of apparent expansion is $\gamma_1$ and the coefficient of linear expansion is $\alpha$. Thus,the coefficient of volume expansion is $\gamma_A = 3\alpha$.Therefore,$\gamma_{	ext{real}} = \gamma_1 + 3\alpha$.For vessel $B$,the coefficient of apparent expansion is $\gamma_2$ and let the coefficient of linear expansion be $\alpha_B$. Thus,the coefficient of volume expansion is $\gamma_B = 3\alpha_B$.Therefore,$\gamma_{	ext{real}} = \gamma_2 + 3\alpha_B$.Since $\gamma_{	ext{real}}$ is the same for the liquid in both cases,we equate the two expressions:$\gamma_1 + 3\alpha = \gamma_2 + 3\alpha_B$.Rearranging for $\alpha_B$:$3\alpha_B = \gamma_1 - \gamma_2 + 3\alpha$.$\alpha_B = \frac{\gamma_1 - \gamma_2}{3} + \alpha$.

The coefficients of apparent expansion of a liquid when determined using two different vessels $A$ and $B$ are $\gamma_1$ and $\gamma_2$,respectively. If the coefficient of linear expansion of the vessel $A$ is $\alpha$,the coefficient of linear expansion of the vessel $B$ is

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