The coercivity of a magnet,where the ferromag | vedclass

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(A) The coercivity $H$ represents the magnetic field intensity required to demagnetize a ferromagnetic material.For a solenoid,the magnetic field inte

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$3 	ext{ A}$

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(A) The coercivity $H$ represents the magnetic field intensity required to demagnetize a ferromagnetic material.For a solenoid,the magnetic field intensity $H$ is given by the formula $H = nI$,where $n$ is the number of turns per unit length and $I$ is the current.Given:Coercivity $H = 3 	imes 10^{3} 	ext{ A m}^{-1}$Number of turns per unit length $n = 1000 	ext{ turns m}^{-1} = 10^{3} 	ext{ m}^{-1}$Using the formula $I = \frac{H}{n}$:$I = \frac{3 	imes 10^{3}}{10^{3}} = 3 	ext{ A}$Therefore,the minimum current required is $3 	ext{ A}$.

The coercivity of a magnet,where the ferromagnet gets completely demagnetized,is $3 \times 10^{3} \text{ A m}^{-1}$. The minimum current required to be passed in a solenoid having $1000 \text{ turns m}^{-1}$,so that the magnet gets completely demagnetized when placed inside the solenoid,is:

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