(D) The current sensitivity of a galvanometer is defined as the deflection produced per unit current,given by the formula: $\frac{\theta}{i} = \frac{N

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(D) The current sensitivity of a galvanometer is defined as the deflection produced per unit current,given by the formula: $\frac{\theta}{i} = \frac{NBA}{k}$.Given:Number of turns $N = 100$Magnetic field $B = 5 \, T$Area $A = 1 \, cm^2 = 10^{-4} \, m^2$Restoring couple per unit radian $k = 10^{-8} \, N \cdot m/rad$.Substituting the values:$\frac{\theta}{i} = \frac{100 \times 5 \times 10^{-4}}{10^{-8}}$$\frac{\theta}{i} = \frac{5 \times 10^{-2}}{10^{-8}} = 5 \times 10^6 \, rad/A$.Since $1 \, A = 10^6 \, \mu A$,we have:$\frac{\theta}{i} = 5 \times 10^6 \times 10^{-6} \, rad/\mu A = 5 \, rad/\mu A$.

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

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The coil of a galvanometer consists of $100$ turns and an effective area of $1 \, cm^2$. The restoring couple per unit radian is $10^{-8} \, N \cdot m/rad$. The magnetic field between the pole pieces is $5 \, T$. The current sensitivity of this galvanometer will be:

A
$5 \times 10^4 \, rad/\mu A$
B
$5 \times 10^{-6} \, rad/A$
C
$2 \times 10^{-7} \, rad/A$
D
$5 \, rad/\mu A$

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Moving Charges and Magnetism

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The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

$A$ moving coil galvanometer has $100$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \ V$,the resistance in Ohm's needed to be connected in series with the coil will be

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When a resistance of $200\Omega$ is connected in series with a galvanometer of resistance $G$, its range is $V$. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is (in $\Omega$)

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When a galvanometer is shunted by a resistance $s$,its current capacity increases $n$ times. If the same galvanometer is shunted by another resistance $s_1$,its capacity will increase to $n_1$ times the original current. The value of $n_1$ is

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When a galvanometer is shunted by a resistance $S$, its current capacity increases $n$ times. If the same galvanometer is shunted by another resistance $S'$, its current capacity will increase to $n'$. The value of $n$ in terms of $n'$, $S$, and $S'$ is

DifficultMHT CET 2026

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Explain the use of a galvanometer as a voltmeter.

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The coil of a galvanometer consists of $100$ turns and an effective area of $1 \, cm^2$. The restoring couple per unit radian is $10^{-8} \, N \cdot m/rad$. The magnetic field between the pole pieces is $5 \, T$. The current sensitivity of this galvanometer will be:

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$A$ moving coil galvanometer has $100$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \ V$,the resistance in Ohm's needed to be connected in series with the coil will be

When a resistance of $200\Omega$ is connected in series with a galvanometer of resistance $G$, its range is $V$. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is (in $\Omega$)

When a galvanometer is shunted by a resistance $s$,its current capacity increases $n$ times. If the same galvanometer is shunted by another resistance $s_1$,its capacity will increase to $n_1$ times the original current. The value of $n_1$ is

When a galvanometer is shunted by a resistance $S$, its current capacity increases $n$ times. If the same galvanometer is shunted by another resistance $S'$, its current capacity will increase to $n'$. The value of $n$ in terms of $n'$, $S$, and $S'$ is

Explain the use of a galvanometer as a voltmeter.

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