The coil of inductance 0.25 mH has a reactanc | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The inductive reactance $X_L$ is given by the formula $X_L = 2 \pi f L$,where $f$ is the frequency and $L$ is the inductance.Rearranging for frequ

Vedclass · Accepted Answer

$210$

Vedclass · Answer

(A) The inductive reactance $X_L$ is given by the formula $X_L = 2 \pi f L$,where $f$ is the frequency and $L$ is the inductance.Rearranging for frequency,we get $f = \frac{X_L}{2 \pi L}$.Given values: $X_L = 330 \Omega$ and $L = 0.25 mH = 0.25 	imes 10^{-3} H$.Substituting the values: $f = \frac{330}{2 	imes (22/7) 	imes 0.25 	imes 10^{-3}}$.$f = \frac{330 	imes 7}{2 	imes 22 	imes 0.25 	imes 10^{-3}} = \frac{2310}{11 	imes 10^{-3}} = 210 	imes 10^3 Hz = 210 kHz$.

The coil of inductance $0.25 mH$ has a reactance of $330 \Omega$,when connected to an a.c. source. The frequency of the a.c. source is (Take $\pi = \frac{22}{7}$) (in $kHz$)

Similar Questions

Discuss the power in an $AC$ circuit containing only an inductor.

The current and $EMF$ through an inductance differ in phase by

$A$ capacitor of $50 \mu F$ is connected to a power source $V = 220 \sin 50 t$ (where $V$ is in volt and $t$ is in second). Find the value of the $rms$ current (in ampere).

In the case of an inductor,

Explain the representation of $AC$ current and voltage by rotating vectors.

Vedclass Test Series

Exam Paper Generator

Online Exam Module