The colorless species is

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To determine the color of the species,we look at the oxidation state of Vanadium $(V)$ and the presence of unpaired $d$-electrons.$1$. In $VCl_3$,

Vedclass · Accepted Answer

$Na_3VO_4$

Vedclass · Answer

(C) To determine the color of the species,we look at the oxidation state of Vanadium $(V)$ and the presence of unpaired $d$-electrons.$1$. In $VCl_3$,$V$ is in the $+3$ oxidation state ($3d^2$ configuration). It has unpaired electrons and is colored.$2$. In $VOSO_4$,$V$ is in the $+4$ oxidation state ($3d^1$ configuration). It has one unpaired electron and is colored.$3$. In $Na_3VO_4$,$V$ is in the $+5$ oxidation state ($3d^0$ configuration). There are no $d$-electrons available for $d-d$ transitions,making it colorless.$4$. In $[V(H_2O)_6]SO_4 \cdot H_2O$,$V$ is in the $+2$ oxidation state ($3d^3$ configuration). It has unpaired electrons and is colored.Therefore,the colorless species is $Na_3VO_4$.

Similar Questions

Name the oxometal anions of the first series of the transition metals in which the metal exhibits the oxidation state equal to its group number.

Excess of $KI$ reacts with $CuSO_4$ solution and then $Na_2S_2O_3$ solution is added to it. Which of the statements is incorrect for this reaction?

The colour of $K_2Cr_2O_7$ changes from red-orange to lemon-yellow on treatment with aqueous $KOH$ because of:

The spin only magnetic moment $(\mu)$ value $(B.M.)$ of the compound with strongest oxidising power among $Mn_2O_3$,$TiO$,and $VO$ is $....$ $B.M.$ (Nearest integer).

Which of the following is used in the manufacture of high refractive index optical glass for cameras?

Vedclass Test Series

Exam Paper Generator

Online Exam Module